The most direct way to allocate an object in an obstack is with
obstack_alloc
, which is invoked almost like malloc
.
This allocates an uninitialized block of size bytes in an obstack and returns its address. Here obstack-ptr specifies which obstack to allocate the block in; it is the address of the
struct obstack
object which represents the obstack. Each obstack function or macro requires you to specify an obstack-ptr as the first argument.This function calls the obstack's
obstack_chunk_alloc
function if it needs to allocate a new chunk of memory; it callsobstack_alloc_failed_handler
if allocation of memory byobstack_chunk_alloc
failed.
For example, here is a function that allocates a copy of a string str
in a specific obstack, which is in the variable string_obstack
:
struct obstack string_obstack; char * copystring (char *string) { size_t len = strlen (string) + 1; char *s = (char *) obstack_alloc (&string_obstack, len); memcpy (s, string, len); return s; }
To allocate a block with specified contents, use the function
obstack_copy
, declared like this:
This allocates a block and initializes it by copying size bytes of data starting at address. It calls
obstack_alloc_failed_handler
if allocation of memory byobstack_chunk_alloc
failed.
Like
obstack_copy
, but appends an extra byte containing a null character. This extra byte is not counted in the argument size.
The obstack_copy0
function is convenient for copying a sequence
of characters into an obstack as a null-terminated string. Here is an
example of its use:
char * obstack_savestring (char *addr, int size) { return obstack_copy0 (&myobstack, addr, size); }
Contrast this with the previous example of savestring
using
malloc
(see Basic Allocation).